0,12=0,12x^2+6

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Solution for 0,12=0,12x^2+6 equation: 



0.12=0.12x^2+6

We move all terms to the left:

0.12-(0.12x^2+6)=0

We get rid of parentheses

-0.12x^2-6+0.12=0

We add all the numbers together, and all the variables

-0.12x^2-5.88=0

a = -0.12; b = 0; c = -5.88;
Δ = b2-4ac
Δ = 02-4·(-0.12)·(-5.88)
Δ = -2.8224
Delta is less than zero, so there is no solution for the equation

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